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<H2><A NAME="SECTION001224000000000000000">
Compound filters</A>
</H2>
<P>
We can use the recirculating and non-recirculating filters developed here to
create a
<A NAME="10201"></A><A NAME="10202"></A><I>compound filter</I> by putting several elementary ones in series. If the parameters
of the non-recirculating ones (of the first type) are <!-- MATH
${Q_1}, \ldots, {Q_j}$
-->
<IMG
WIDTH="77" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img887.png"
ALT="${Q_1}, \ldots, {Q_j}$">
and those of the recirculating ones are <!-- MATH
${P_1}, \ldots, {P_k}$
-->
<IMG
WIDTH="74" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img888.png"
ALT="${P_1}, \ldots, {P_k}$">, then putting
them all in series, in any order, will give the transfer function:
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
H(Z) = {
{
(1 - {Q_1}{Z^{-1}}) \cdots (1 - {Q_j}{Z^{-1}})
} \over {
(1 - {P_1}{Z^{-1}}) \cdots (1 - {P_k}{Z^{-1}})
}
}
\end{displaymath}
-->
<IMG
WIDTH="263" HEIGHT="45" BORDER="0"
SRC="img889.png"
ALT="\begin{displaymath}
H(Z) = {
{
(1 - {Q_1}{Z^{-1}}) \cdots (1 - {Q_j}{Z^{-1}})
} \over {
(1 - {P_1}{Z^{-1}}) \cdots (1 - {P_k}{Z^{-1}})
}
}
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
The frequency response of the resulting compound filter is the product of
those of
the elementary ones. (One could also combine elementary filters by adding
their outputs, or making more complicated networks of them; but for most
purposes the series configuration is the easiest one to work with.)
<P>
<BR><HR>
<ADDRESS>
Miller Puckette
2006-12-30
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