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<H2><A ID="SECTION001433000000000000000">
Square and symmetric triangle waves</A>
</H2>
<P>
<DIV ALIGN="CENTER"><A ID="fig10.06"></A><A ID="14409"></A>
<TABLE>
<CAPTION ALIGN="BOTTOM"><STRONG>Figure 10.6:</STRONG>
Symmetric triangle wave, obtained by superposing parabolic waves with
<IMG
WIDTH="46" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img66.png"
ALT="$(M, c)$"> pairs equal to <IMG
WIDTH="38" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img67.png"
ALT="$(0, 8)$"> and <IMG
WIDTH="72" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img68.png"
ALT="$(N/2, -8)$">.</CAPTION>
<TR><TD><IMG
WIDTH="473" HEIGHT="97" BORDER="0"
SRC="img1334.png"
ALT="\begin{figure}\psfig{file=figs/fig10.06.ps}\end{figure}"></TD></TR>
</TABLE>
</DIV>
<P>
To see how to obtain Fourier series for classical waveforms in general,
consider first the square wave,
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
x[n] = s[n] - s[n-{N \over 2}]
\end{displaymath}
-->
<IMG
WIDTH="155" HEIGHT="39" BORDER="0"
SRC="img1335.png"
ALT="\begin{displaymath}
x[n] = s[n] - s[n-{N \over 2}]
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
equal to <IMG
WIDTH="27" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img98.png"
ALT="$1/2$"> for the first half cycle (<IMG
WIDTH="104" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img1336.png"
ALT="$0 &lt;= n &lt; N/2$">) and <IMG
WIDTH="39" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img212.png"
ALT="$-1/2$"> for the rest.
We get the Fourier series by plugging in the Fourier series for <IMG
WIDTH="29" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img1311.png"
ALT="$s[n]$"> twice:
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
x[n] \approx {1 \over \pi} \left [
{\sin ( \omega n )}
+ {{\sin ( 2 \omega n)} \over 2}
+ {{\sin ( 3 \omega n)} \over 3}
+ \cdots
\right .
\end{displaymath}
-->
<IMG
WIDTH="327" HEIGHT="45" BORDER="0"
SRC="img1337.png"
ALT="\begin{displaymath}
x[n] \approx {1 \over \pi} \left [
{\sin ( \omega n )}
+ ...
...\over 2}
+ {{\sin ( 3 \omega n)} \over 3}
+ \cdots
\right .
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
\left .
-{\sin ( \omega n )}
+ {{\sin ( 2 \omega n)} \over 2}
- {{\sin ( 3 \omega n)} \over 3}
\pm \cdots
\right ]
\end{displaymath}
-->
<IMG
WIDTH="272" HEIGHT="45" BORDER="0"
SRC="img1338.png"
ALT="\begin{displaymath}
\left .
-{\sin ( \omega n )}
+ {{\sin ( 2 \omega n)} \over 2}
- {{\sin ( 3 \omega n)} \over 3}
\pm \cdots
\right ]
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
= {2 \over \pi} \left [
{\sin ( \omega n )}
+ {{\sin ( 3 \omega n)} \over 3}
+ {{\sin ( 5 \omega n)} \over 5}
+ \cdots
\right ]
\end{displaymath}
-->
<IMG
WIDTH="300" HEIGHT="45" BORDER="0"
SRC="img1339.png"
ALT="\begin{displaymath}
= {2 \over \pi} \left [
{\sin ( \omega n )}
+ {{\sin ( 3 ...
...\over 3}
+ {{\sin ( 5 \omega n)} \over 5}
+ \cdots
\right ]
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
<P>
The symmetric triangle wave (Figure <A HREF="#fig10.06">10.6</A>) given by
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
x[n] = 8 p[n] - 8 p[n-{N \over 2}]
\end{displaymath}
-->
<IMG
WIDTH="173" HEIGHT="39" BORDER="0"
SRC="img1340.png"
ALT="\begin{displaymath}
x[n] = 8 p[n] - 8 p[n-{N \over 2}]
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
similarly comes to
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
x[n] \approx {8 \over {{\pi^2}}} \left [
{\cos ( \omega n )}
+ {{\cos ( 3 \omega n)} \over 9}
+ {{\cos ( 5 \omega n)} \over 25}
+ \cdots
\right ]
\end{displaymath}
-->
<IMG
WIDTH="345" HEIGHT="45" BORDER="0"
SRC="img1341.png"
ALT="\begin{displaymath}
x[n] \approx {8 \over {{\pi^2}}} \left [
{\cos ( \omega n ...
...over 9}
+ {{\cos ( 5 \omega n)} \over 25}
+ \cdots
\right ]
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
<P>
<BR><HR>
<ADDRESS>
Miller Puckette
2006-12-30
</ADDRESS>
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