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<H2><A NAME="SECTION001223000000000000000"></A>
<A NAME="sect8.recirculating"></A>
<BR>
Elementary recirculating filter
</H2>
<P>
The
<A NAME="10185"></A><A NAME="10186"></A><I>elementary recirculating filter</I> is the recirculating comb filter of
Figure <A HREF="node109.html#fig07.07">7.7</A> with a
complex-valued feedback gain <IMG
WIDTH="15" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img880.png"
ALT="$P$"> as shown in Figure <A HREF="#fig08.11">8.11</A> (part
a). By the same analysis as before, feeding this network a sinusoid whose
<IMG
WIDTH="13" HEIGHT="13" ALIGN="BOTTOM" BORDER="0"
SRC="img75.png"
ALT="$n$">th sample is <IMG
WIDTH="24" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img653.png"
ALT="$Z^n$"> gives an output of:
<BR><P></P>
<DIV ALIGN="CENTER">
<!-- MATH
\begin{displaymath}
{{1} \over {1 - P {Z^{-1}}}} {Z^n}
\end{displaymath}
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<IMG
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{{1} \over {1 - P {Z^{-1}}}} {Z^n}
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<P></P>
so the transfer function is
<BR><P></P>
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<!-- MATH
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H(Z) = {{1} \over {1 - P {Z^{-1}}}}
\end{displaymath}
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<IMG
WIDTH="131" HEIGHT="40" BORDER="0"
SRC="img882.png"
ALT="\begin{displaymath}
H(Z) = {{1} \over {1 - P {Z^{-1}}}}
\end{displaymath}">
</DIV>
<BR CLEAR="ALL">
<P></P>
The recirculating filter is stable when <IMG
WIDTH="53" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img883.png"
ALT="$\vert P\vert &lt; 1$">; when, instead, <IMG
WIDTH="53" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img884.png"
ALT="$\vert P\vert&gt; 1$"> the
output grows exponentially as the delayed sample recirculates.
<P>
<DIV ALIGN="CENTER"><A NAME="fig08.11"></A><A NAME="10197"></A>
<TABLE>
<CAPTION ALIGN="BOTTOM"><STRONG>Figure 8.11:</STRONG>
The elementary recirculating filter: (a) block diagram; (b)
frequency response.</CAPTION>
<TR><TD><IMG
WIDTH="454" HEIGHT="259" BORDER="0"
SRC="img885.png"
ALT="\begin{figure}\psfig{file=figs/fig08.11.ps}\end{figure}"></TD></TR>
</TABLE>
</DIV>
<P>
The transfer function is thus just the inverse of that of the non-recirculating
filter (first form). If you put the two in series with <IMG
WIDTH="49" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img886.png"
ALT="$P=Q$">, the output
theoretically equals the input. (This analysis only demonstrates it for
sinusoidal inputs; that it follows for other signals as well can be verified by
working out the impulse response of the combined network).
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Miller Puckette
2006-12-30
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