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<H1><A NAME="SECTION001440000000000000000">
Predicting and controlling foldover</A>
</H1>
<P>
Now we descend to the real situation, in which the period of the waveform
cannot be assumed to be arbitrarily long and integer-valued. Suppose (for
definiteness) we want to synthesize tones at 440 Hertz (A above middle C), and
that we are using a sample rate of 44100 Hertz, so that the period is about 100.25
samples. Theoretically, given a very high sample rate, we would expect the
fiftieth partial to have magnitude <IMG
WIDTH="35" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img1365.png"
ALT="$1/50$"> compared to the fundamental and
a frequency about 20 kHz. If we sample this waveform at the (lower) sample
rate of 44100, then partials in excess of this frequency will be aliased, as
described in Section <A HREF="node41.html#sect3.sampling">3.1</A>. The relative strength of the
folded-over partials will be on the order of -32 decibels--quite audible.
If the fundamental frequency is raised further, more and louder partials reach
the Nyquist frequency (half the sample rate) and begin to fold over.
<P>
Foldover problems are much less pronounced for waveforms with only corners
(instead of jumps) because of the faster dropoff of higher partial frequencies;
for instance, a symmetric triangle wave at 440 Hertz would get twice the dropoff, or -64
decibels. In general, though, waveforms with discontinuities are a better
starting point for
<A NAME="14464"></A>subtractive synthesis (the most popular classical technique).
In case you were hoping, subtractive filtering can't remove foldover once it is
present in an audio signal.
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<LI><A NAME="tex2html3456"
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<LI><A NAME="tex2html3457"
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<ADDRESS>
Miller Puckette
2006-12-30
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